(5x^2+4)-(4y^2+4)=

Solution for (5x^2+4)-(4y^2+4)= equation:

Simplifying
(5x2 + 4) + -1(4y2 + 4) = 0

Reorder the terms:
(4 + 5x2) + -1(4y2 + 4) = 0

Remove parenthesis around (4 + 5x2)
4 + 5x2 + -1(4y2 + 4) = 0

Reorder the terms:
4 + 5x2 + -1(4 + 4y2) = 0
4 + 5x2 + (4 * -1 + 4y2 * -1) = 0
4 + 5x2 + (-4 + -4y2) = 0

Reorder the terms:
4 + -4 + 5x2 + -4y2 = 0

Combine like terms: 4 + -4 = 0
0 + 5x2 + -4y2 = 0
5x2 + -4y2 = 0

Solving
5x2 + -4y2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '4y2' to each side of the equation.
5x2 + -4y2 + 4y2 = 0 + 4y2

Combine like terms: -4y2 + 4y2 = 0
5x2 + 0 = 0 + 4y2
5x2 = 0 + 4y2
Remove the zero:
5x2 = 4y2

Divide each side by '5'.
x2 = 0.8y2

Simplifying
x2 = 0.8y2

Take the square root of each side:
x = {-0.894427191y, 0.894427191y}